I wish I could take credit, but the credit must go to my dear friend AquaRapid. Check out this pythonic goodness:
[ x[0] for x in sorted(dictionaryToSortByKeyValues.items(),
lambda x, y: cmp(x[1], y[1])) ]
Thursday, July 19, 2007
Python Tip of the Day
Have you ever wanted to sort the keys of a python dictionary by their values?
I wish I could take credit, but the credit must go to my dear friend AquaRapid. Check out this pythonic goodness:
I wish I could take credit, but the credit must go to my dear friend AquaRapid. Check out this pythonic goodness:
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1 comments:
Nice page, well done.
What about:
from operator import itemgetter
[k for k, v in sorted(d.iteritems(), key=itemgetter(1))]
A timing comparison on a dictionary of 100000 items gives 0.67 seconds for this and 2.1 seconds for the one above. The additional function calls via the lambda function introduces a bit of overhead... Just a thought.
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